A Ruby code example or code snippet to check leap year. This code is showing you how to create a simple Ruby program that checks whether a year is a leap year. According to Wikipedia: a leap year is a year that has one additional day in order to adjust the calendar to the astronomical year.
The logic to check for leap year:
- if (year is not divisible by 4) then (it is a common year)
- else if (year is not divisible by 100) then (it is a leap year)
- else if (year is not divisible by 400) then (it is a common year)
- else (it is a leap year)
The years input that we will give & its expected output are:
- 2020 is a leap year
- 2019 is not a leap year
- 2018 is not a leap year
- 2000 is a leap year
- 1900 is not a leap year
Ruby Code Example to Check for Leap Year You can immediately run the following code in various IDEs that have Dart interpreters such as VS Code, Atom, or CMD.
The following Ruby program code uses the Nested If and Comparison Operators.
puts "Input year: "
year = gets.chomp.to_i
if yr % 400 == 0
puts "#{year} is a leap year"
elsif yr % 4 == 0 && yr % 100 !=0
puts "#{year} is a leap year"
else
puts "#{year} is not a leap year"
end
Output
Input year:
2020 is a leap year
Input year: 2019
2019 is not a leap year
Input year: 2018
2019 is not a leap year
Input year: 2000
2000 is a leap year
Input year: 1900
1900 is not a leap year
Hopefully, this sample Ruby code exaple for checking leap years is useful.
